(x^2+3x)/(3x+1)^2

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Solution for (x^2+3x)/(3x+1)^2 equation: 


D( x )

(3*x+1)^2 = 0

(3*x+1)^2 = 0

(3*x+1)^2 = 0

3*x+1 = 0 // - 1

3*x = -1 // : 3

x = -1/3

x in (-oo:-1/3) U (-1/3:+oo)

(x^2+3*x)/((3*x+1)^2) = 0

x^2+3*x = 0

x*(x+3) = 0

x+3 = 0 // - 3

x = -3

x*(x+3) = 0

(x*(x+3))/((3*x+1)^2) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x )

x = 0

x in { -3, 0 }

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